Đề thi học kỳ 1 Toán 9 năm 2025 — Trường THCS Trần Quý Cáp, Đà Nẵng

$\displaystyle 4x^{2} + 5y = 7$

$\displaystyle x + 2y^{2} = 5$

$\displaystyle 3x^{2} - 2y^{2} = 0$

$\displaystyle 2x + 5y = 9$

$\displaystyle 2a \leq 2b$

$\displaystyle 3a > 3b$

$\displaystyle 4a < 4b$

$\displaystyle 5a \leq 5b$

4 và -4

2

16

2 và -2

$\displaystyle 2\sqrt{5}$

$\displaystyle 10\sqrt{5}$

$\displaystyle 5\sqrt{2}$

$\displaystyle 25\sqrt{2}$

$\displaystyle a\sqrt{b} = \sqrt{ab}$

$\displaystyle a\sqrt{b} = -\sqrt{ab}$

$\displaystyle a\sqrt{b} = \sqrt{ab^{2}}$

$\displaystyle a\sqrt{b} = \sqrt{a^{2}b}$

$\displaystyle \cos\alpha = \dfrac{BC}{AC}$

$\displaystyle \cos\alpha = \dfrac{AB}{BC}$

$\displaystyle \cos\alpha = \dfrac{AB}{AC}$

$\displaystyle \cos\alpha = \dfrac{BC}{AB}$

$\displaystyle \dfrac{1}{2}$

$\displaystyle \dfrac{\sqrt{3}}{2}$

$\displaystyle \dfrac{\sqrt{2}}{2}$

$\displaystyle \sqrt{3}$

$\displaystyle 34^{\circ}$

$\displaystyle 35^{\circ}$

$\displaystyle 34,7^{\circ}$

$\displaystyle 0,01^{\circ}$

$\displaystyle \sin B = \dfrac{AC}{AB}$

$\displaystyle \sin B = \dfrac{AB}{AC}$

$\displaystyle \sin B = \dfrac{AC}{BC}$

$\displaystyle \sin B = \dfrac{AB}{BC}$

$\displaystyle 30^{\circ}$

$\displaystyle 60^{\circ}$

$\displaystyle 90^{\circ}$

$\displaystyle 120^{\circ}$

$\displaystyle l = \dfrac{n}{360}\pi R$

$\displaystyle l = \dfrac{n}{180}\pi R$

$\displaystyle l = \dfrac{180}{n}\pi R$

$\displaystyle l = \dfrac{360}{R}\pi n$