Đề kiểm tra giữa kỳ 2 Toán 8 năm 2024 — Trường THCS xã Tây Yên A, Kiên GiangMã đề 1

$\displaystyle \frac{5y^3z}{x^2}$

$\displaystyle \frac{xy-z}{2}$

$\displaystyle 3x-2$

$\displaystyle \frac{y+z}{0}$

$\displaystyle \frac{3y^2}{9xy^2}$

$\displaystyle \frac{y^2}{9xy^2}$

$\displaystyle \frac{3y^2}{9xy}$

$\displaystyle \frac{3y}{9xy^2}$

$\displaystyle x \neq -2$

$\displaystyle x \neq 1$

$\displaystyle x = 2$

$\displaystyle x \neq 2$

$\displaystyle 3x^2(x-2)$

$\displaystyle x-2$

$\displaystyle 3x(x-2)$

$\displaystyle 3x(x-2)^2$

$\displaystyle \frac{7x}{6y}$

$\displaystyle \frac{7x-2y}{3y}$

$\displaystyle \frac{7x+2y}{3y}$

$\displaystyle \frac{7x}{3y}$

$\displaystyle \frac{-8}{7}$

$\displaystyle \frac{6xy-8}{7}$

$\displaystyle \frac{6xy+8}{7}$

$\displaystyle -\frac{6xy-8}{7}$

$\displaystyle \frac{2x^2}{3y}$

$\displaystyle \frac{4z^3}{9x^2}$

$\displaystyle \frac{2z^2}{3x}$

$\displaystyle \frac{4x^2}{9y}$

$\displaystyle \frac{x + 1}{x - 1}$

$\displaystyle \frac{x - 1}{x + 1}$

$\displaystyle \frac{x - 1}{5(x + 1)}$

$\displaystyle \frac{x + 1}{5(x - 1)}$

$\displaystyle \Delta HIG \sim \Delta DEF$

$\displaystyle \Delta IGH \sim \Delta DEF$

$\displaystyle \Delta HIG \sim \Delta DFE$

$\displaystyle \Delta HGI \sim \Delta DEF$

$\displaystyle k' = 2$

$\displaystyle k' = 5$

$\displaystyle k' = \frac{2}{5}$

$\displaystyle k' = \frac{5}{2}$