Đề kiểm tra giữa kỳ 2 Toán 7 năm 2026 — Trường THCS Cao Lộc, Lạng SơnMã đề 701

$\displaystyle \frac{x}{3} = \frac{y}{5}$

$\displaystyle \frac{x}{y} = \frac{x+5}{y-3}$

$\displaystyle \frac{x}{y} = \frac{x+5}{y+3}$

$\displaystyle \frac{x}{y} = \frac{x+3}{y+5}$

$\displaystyle \frac{a}{7} = \frac{b}{8} = \frac{c}{5}$

$\displaystyle \frac{a}{5} = \frac{b}{7} = \frac{c}{8}$

$\displaystyle \frac{a}{7} = \frac{b}{5} = \frac{c}{8}$

$\displaystyle \frac{a}{5} = \frac{b}{8} = \frac{c}{7}$

$\frac{2}{6}$ và $\frac{4}{3}$

$\frac{4}{12}$ và $\frac{4}{9}$

$\frac{1}{3}$ và $\frac{4}{9}$

$\frac{1}{3}$ và $\frac{4}{12}$

$\displaystyle \widehat{C} < \widehat{A} < \widehat{B}$

$\displaystyle \widehat{B} < \widehat{C} < \widehat{A}$

$\displaystyle \widehat{C} < \widehat{B} < \widehat{A}$

$\displaystyle \widehat{A} < \widehat{B} < \widehat{C}$

-4

-2

-3

-1

$\displaystyle IB > IC$

$\displaystyle IB + IC < BC$

$\displaystyle IB = IC$

$\displaystyle IB < IC$

$\displaystyle y = 7 + x$

$\displaystyle y = \frac{x}{7}$

$\displaystyle y = \frac{7}{x}$

$\displaystyle y = 7x$

$\displaystyle \frac{-8}{5} = \frac{10}{-16}$

$\displaystyle \frac{-8}{-16} = \frac{10}{5}$

$\displaystyle \frac{5}{-8} = \frac{10}{-16}$

$\displaystyle \frac{-8}{10} = \frac{-16}{5}$

-3

$\displaystyle \frac{-1}{3}$

$\displaystyle \frac{1}{3}$

3