Đề kiểm tra giữa kỳ 2 Toán 7 năm 2024 — Trường THCS La Phù, Hà NộiMã đề 1

$\displaystyle \frac{3}{-9} = \frac{5}{-15}$

$\displaystyle \frac{3}{5} = \frac{-15}{-9}$

$\displaystyle \frac{5}{3} = \frac{-9}{-15}$

$\displaystyle \frac{3}{5} = \frac{15}{9}$

$\displaystyle a = c$

$\displaystyle a.c = b.d$

$\displaystyle a.d = b.c$

$\displaystyle b = d$

$\displaystyle x = 3$

$\displaystyle x = -3$

$\displaystyle x = -2$

$\displaystyle x = 8$

$\displaystyle 6$

$\displaystyle -6$

$\displaystyle -3$

$\displaystyle 2$

$\displaystyle \frac{x}{4} = \frac{y}{2} = \frac{z}{5}$

$\displaystyle \frac{x}{2} = \frac{y}{5} = \frac{z}{4}$

$\displaystyle \frac{x}{2} = \frac{y}{4} = \frac{z}{5}$

$\displaystyle \frac{x}{5} = \frac{y}{4} = \frac{z}{2}$

$\displaystyle 4$

$\displaystyle -4$

$\displaystyle 0$

$\displaystyle -16$

$\displaystyle x^{2} + 2x + 1$

$\displaystyle x^{3} + 2x^{2} + x$

$\displaystyle x^{2} - 1$

$\displaystyle x^{4} + 2x - 3$

$\displaystyle \widehat{C} < \widehat{B} < \widehat{A}$

$\displaystyle \widehat{C} > \widehat{B} > \widehat{A}$

$\displaystyle \widehat{A} < \widehat{B} < \widehat{C}$

$\displaystyle \widehat{A} < \widehat{C} < \widehat{B}$

$\displaystyle MN < MP + PN$

$\displaystyle MN < MP - PN$

$\displaystyle MP - PN = MN$

$\displaystyle NP > MN + MP$

$\displaystyle AB$

$\displaystyle BC$

$\displaystyle AC$

$\displaystyle BA$

$\displaystyle NP > MP$

$\displaystyle NP < MN$

$\displaystyle MP > MN$

$\displaystyle NP < MP$