Đề kiểm tra giữa kỳ 1 Toán 9 năm 2025 — Trường PTDTBT THCS Đinh Ruối, Gia LaiMã đề 1

$\displaystyle x=3$

$\displaystyle x=-7$

$\displaystyle x=3, x=-7$

$\displaystyle x=-3, x=7$

$\displaystyle x=0$

$\displaystyle x=2024$

$\displaystyle x=2025$

Đáp án A, B, C

$\displaystyle x \neq 0, x \neq -4$

$\displaystyle x \neq 0, x \neq 4$

$\displaystyle x \neq 0$

$\displaystyle x \neq -4$

$\displaystyle 2x-y=1$

$\displaystyle 0x+3y=9$

$\displaystyle 5x-0y=11$

$\displaystyle 2x^{2}+y=12$

$\displaystyle (1;-2)$

$\displaystyle (1;2)$

$\displaystyle (-2;1)$

$\displaystyle (2;1)$

$\displaystyle 2x-y=1$

$\displaystyle x^{2}+3y=8$

$\displaystyle 5x=11$

$\displaystyle 2x^{2}+y=12$

$\displaystyle \frac{1}{2}$

$\displaystyle \frac{\sqrt{2}}{2}$

$\displaystyle \frac{\sqrt{3}}{2}$

$\displaystyle 1$

$\displaystyle \frac{1}{2}$

$\displaystyle \frac{\sqrt{2}}{2}$

$\displaystyle \frac{\sqrt{3}}{3}$

$\displaystyle 1$

$\displaystyle \sin \alpha$

$\displaystyle \cos \alpha$

$\displaystyle \tan \alpha$

$\displaystyle \cot \alpha$

$\displaystyle \frac{1}{2}$

$\displaystyle \frac{\sqrt{2}}{2}$

$\displaystyle \frac{\sqrt{3}}{2}$

$\displaystyle \frac{\sqrt{3}}{3}$

$\displaystyle \frac{1}{2}$

$\displaystyle \frac{\sqrt{2}}{2}$

$\displaystyle \frac{\sqrt{3}}{2}$

$\displaystyle 1$