Đề kiểm tra giữa kỳ 1 Toán 8 năm 2024 — Trường THCS Ngọc Lâm, Hà NộiMã đề 801

$\displaystyle x^2 - 1$

$\displaystyle \frac{2x-1}{5y}$

$\displaystyle 4xy^2$

$\displaystyle 5x - 7$

$\displaystyle 2x^2y^5$

$\displaystyle -2x^3y^6$

$\displaystyle 2x^3y^5$

$\displaystyle -2x^3y^5$

$\displaystyle 7xy$

$\displaystyle \frac{5}{2}x^2y^5$

$\displaystyle 7x^7$

$\displaystyle -7x^5y^2$

$\displaystyle \frac{x - y}{x + y}$

$\displaystyle \frac{4x + 3}{7xy}$

$\displaystyle \frac{3x - y}{\frac{7}{x}}$

$\displaystyle x^2 + 3y$

$\displaystyle \frac{-14x}{12y^2}$

$\displaystyle \frac{-7x^2y^3}{6xy^5}$

$\displaystyle \frac{7x}{6y^2}$

$\displaystyle \frac{7}{6y^2}$

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