Đề kiểm tra giữa kỳ 1 Toán 7 năm 2025 — Trường THCS Trần Quý Cáp, Đà Nẵng

$\displaystyle -12$

$\displaystyle \frac{1}{5}$

$\displaystyle 3,2$

$\displaystyle \frac{4}{0}$

$\displaystyle \frac{-4}{3} \in \mathbb{Z}$

$\displaystyle -4 \in \mathbb{N}$

$\displaystyle 3,2 \in \mathbb{Q}$

$\displaystyle \frac{4}{0} \in \mathbb{Q}$

$\displaystyle -0,75$

$\displaystyle \frac{75}{10}$

$\displaystyle \frac{10}{75}$

$\displaystyle -7,5$

$\displaystyle a > c$

$\displaystyle a < c$

$\displaystyle a \le c$

$\displaystyle c < a$

$\displaystyle \left(\frac{1}{4}\right)^2 = \frac{1}{8}$

$\displaystyle \left(\frac{1}{4}\right)^1 = 1$

$\displaystyle \left(\frac{1}{4}\right)^2 = \frac{1}{16}$

$\displaystyle \left(\frac{1}{4}\right)^0 = 0$

$\displaystyle x^{10} : x^2$

$\displaystyle x^3 \cdot x^2$

$\displaystyle x^8 - x^3$

$\displaystyle x^5 \cdot x$

$\displaystyle 60^0$

$\displaystyle 90^0$

$\displaystyle 120^0$

$\displaystyle 180^0$

$\displaystyle \Delta ABC = \Delta A'B'C'$

$\displaystyle \Delta ABC = \Delta B'A'C'$

$\displaystyle \Delta ABC = \Delta C'B'A'$

$\displaystyle \Delta ABC = \Delta C'A'B'$

$\displaystyle MN = EF$

$\displaystyle MP = DE$

$\displaystyle MN = DF$

$\displaystyle MN = DE$

$\displaystyle \widehat{A_1} + \widehat{B_3} = 180^\circ$

$\displaystyle \widehat{A_2} = \widehat{B_1}$

$\displaystyle \widehat{A_4} = \widehat{B_4}$

$\displaystyle \widehat{A_3} = \widehat{B_4}$