Đề kiểm tra giữa kỳ 1 Toán 7 năm 2025 — Trường THCS Nguyễn Gia Thiều, TP HCMMã đề 001

$\displaystyle \frac{-23}{10}$

$\displaystyle \frac{10}{23}$

$\displaystyle \frac{23}{10}$

$\displaystyle \frac{10}{-23}$

$\displaystyle 2\frac{4}{7}$

$\displaystyle -0,5$

$\displaystyle -8$

$\displaystyle \frac{2}{3}$

$\displaystyle \frac{7}{2}$

$\displaystyle \frac{-7}{2}$

$\displaystyle \frac{2}{7}$

$\displaystyle \frac{-2}{7}$

$\displaystyle \frac{1}{7} - \frac{4}{3} - \frac{1}{8}$

$\displaystyle \frac{1}{7} - \frac{4}{3} + \frac{1}{8}$

$\displaystyle \frac{1}{7} + \frac{4}{3} + \frac{1}{8}$

$\displaystyle \frac{1}{7} + \frac{4}{3} - \frac{1}{8}$

$\displaystyle AD=4\text{cm}$

$\displaystyle NP=4\text{cm}$

$\displaystyle MQ=4\text{cm}$

$\displaystyle MN=4\text{cm}$

$\displaystyle 1,2^{12}$

$\displaystyle 1,2^{18}$

$\displaystyle 1,2^3$

$\displaystyle 1,2^6$

$\displaystyle x=2$

$\displaystyle x=6$

$\displaystyle x=8$

$\displaystyle x=16$

$\displaystyle 30^\circ$

$\displaystyle 40^\circ$

$\displaystyle 130^\circ$

$\displaystyle 140^\circ$

$\displaystyle 80\text{cm}^3$

$\displaystyle 18\text{cm}^3$

$\displaystyle 19\text{cm}^3$

$\displaystyle 90\text{cm}^3$

$\displaystyle 8$

$\displaystyle 9$

$\displaystyle 10$

$\displaystyle 12$

$\displaystyle 2.640\mathrm{cm}^3$

$\displaystyle 836\mathrm{cm}^2$

$\displaystyle 2.640\mathrm{cm}^2$

$\displaystyle 836\mathrm{cm}^3$

$\displaystyle 30^{\circ}$

$\displaystyle 60^{\circ}$

$\displaystyle 150^{\circ}$

$\displaystyle 90^{\circ}$