Đề kiểm tra giữa kỳ 1 Toán 7 năm 2025 — Trường TH & THCS Phúc Sơn 1, Bắc Ninh

$a, b \in \mathbb{Z}$ và $b \neq 0$

$a = 0$ và $b \neq 0$

$\displaystyle a, b \in \mathbb{N}$

$\displaystyle a, b \in \mathbb{N}, b \neq 0$

$\displaystyle 7,9$

$\displaystyle -10$

$\displaystyle \frac{8}{3}$

$\displaystyle 0$

$\displaystyle \frac{9}{8}$

$\displaystyle \frac{9}{-8}$

$\displaystyle \frac{8}{9}$

$\displaystyle -\frac{8}{9}$

$\displaystyle \frac{-11}{3}$

$\displaystyle \frac{-12}{3}$

$\displaystyle \frac{-25}{-4}$

$\displaystyle \frac{5}{-4}$

Q

Z

N

R

$\displaystyle \frac{1}{4}$

$\displaystyle 0$

$\displaystyle -\frac{3}{7}$

$\displaystyle 2$

$\displaystyle [ ] \to ( ) \to \{ \}$

$\displaystyle [ ] \to \{ \} \to ( )$

$\displaystyle \{ \} \to [ ] \to ( )$

$\displaystyle ( ) \to [ ] \to \{ \}$

0

1

-1

$\displaystyle \frac{1}{3}$

$\displaystyle -\frac{4}{25}$

$\displaystyle \frac{4}{25}$

$\displaystyle -\frac{2}{5}$

$\displaystyle \frac{4}{10}$

9

-9

9 và -9

0

$\displaystyle \sqrt{\frac{1}{9}}$

$\displaystyle \sqrt{2}$

0

$\displaystyle \frac{-1}{2}$

$\displaystyle V = 9\text{cm}^3$

$\displaystyle V = 27\text{cm}^3$

$\displaystyle V = 27\text{cm}^2$

$\displaystyle V = 36\text{cm}^3$

3

-3

0

3 và -3

$\displaystyle NF = 7 \text{ cm}$

$\displaystyle NF = 4 \text{ cm}$

$\displaystyle EH = 4 \text{ cm}$

$\displaystyle NP = 7 \text{ cm}$

$\displaystyle V = \dfrac{\sqrt{2}a^3}{3}$

$\displaystyle V = \dfrac{\sqrt{2}a^3}{4}$

$\displaystyle V = \dfrac{\sqrt{3}a^3}{2}$

$\displaystyle V = \dfrac{\sqrt{3}a^3}{4}$